Question

A body undergoes an acceleration of 10m'/s2 starting from rest then the distsnce travelled by it in 5 seconds is

Answer 1

Heya !!

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Acceleration = 10 m / s²
Initial velocity = 0
Time taken = 5 seconds

Now,

V = u + at

=> v = 0 + 10 * 5

=> v = 50 m / s

And,

v² - u² = 2as

=> 50² - 0² = 2 * 10 * s

=> 2500 = 20 * s

=> s = 2500 / 20

=> s = 125 m

Hence, distance is 125 m

Answer 2

For this we can use the second equation of motion

s=ut+1/2a$t^{2}$

Here,

       u=0 m/s(rest)

s=0+ (1/2 x 10 x 5 x 5 )

s=125m

Hope this helpzzz.