Question

a body undergoes uniformly accelerated motion. its velocity after 6 seconds is 22m/s after 10 seconds it is 34m/s. Calculate the distance covered in 12th second.

Answer 1

Explanation:

from the given information acceleration is 3 m/s^2 & initial velocity is 4m/s

distance covered in nth second is u + a(n-0.5)

s = 4+3×23/2

= 38.5 m

Answer 2

Explanation:

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