a body uniformly accelerated from 10 metre per second to 25 metre per second in 5 second. find the velocity after 5 s and distance covered at that time
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Answer:
625
Explanation:
The initial velocity is
u= 0 ms
The acceleration is
a=10m/s
The time is
t=5s
Apply the equation of motion
v=u+at
The velocity is
v=0+10X5=50m/s
The distance travelled in the first 5s is
s=ut+1/2at2=0⋅5+12⋅10⋅52=125m
The distance travelled in the following 10s is
s1=vt1=50X10=500m
The total distance travelled is d
=>s+s1=125+500
=625m
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