Question

a body uniformly accelerated from 10 metre per second to 25 metre per second in 5 second. find the velocity after 5 s and distance covered at that time

Answer 1

Answer:

625

Explanation:

The initial velocity is  

u= 0 ms

The acceleration is  

a=10m/s

The time is

t=5s

Apply the equation of motion

v=u+at

The velocity is

v=0+10X5=50m/s

The distance travelled in the first  5s is

s=ut+1/2at2=0⋅5+12⋅10⋅52=125m

The distance travelled in the following  10s is

s1=vt1=50X10=500m

The total distance travelled is d

=>s+s1=125+500

=625m

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