Physics, asked by byjubenvarghese, 3 months ago

A body vibrates 180 times in 60 seconds. Calculate its frequency and time period?

Answers

Answered by srikanthn711
26

\Large \mathfrak \blue  {⛦Given⛦}

A body vibrates 180 times in 60 seconds.

 \\

\Large \mathfrak \blue {⛦To~find⛦}

We have to find it's frequency and time period.

 \\

\Large \mathfrak \blue {⛦Solution⛦}

  • Total number of vibrations = 180
  • Total time = 60 seconds

\sf \red {⛦~~ Time~period=\cfrac{Total~time}{Total~number~of~vibrations} }

\red \mapsto \sf  \dfrac{\cancel{}60}{180}

\red \mapsto \sf  \dfrac{1}{3}

\red \mapsto \sf 0.33~second

\sf \red {⛦~~Frequency= \cfrac{1}{Time~period} }

\red \mapsto \sf  \dfrac{1}{0.33}

\red \mapsto \sf 3.03Hz

 \\

\sf \green {\therefore~The~time~period~is~0.33seconds~and} \\ \sf \green {frequency~is ~3.03Hz.}

 \\

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Answered by hotcupid16
199

\huge\bold{Given :}

  • An object vibrates 60 times in 4 seconds.

\huge\bold{To~Find :}

  • Find the frequency :-

\bf\blue{We~know~that,} \\

\implies{\sf{\large { \:\:\: \dfrac{Total~time}{No.~of~vibrations}\: }}}

\implies{\sf{\large { \:\:\: \dfrac{60}{180}\: }}}

\implies{\sf{\large { \:\:\: \dfrac{1}{3}\: }}}

⠀⠀

\implies \bf\green{0.33~seconds} \\

\qquad\quad\boxed{\bf{\mid{\overline{\underline{\purple{\bigstar\: Now~find~the~time~period :- :}}}}}\mid}\\\\

\bf\blue{We~know~that,} \\

\implies \bf\red{Frequency =} \\ {\sf{\large { \:\:\: \dfrac{1}{Time~period}\: }}}

\implies{\sf{\large { \:\:\: \dfrac{1}{0.33}\: }}}

\implies \bf\green{3.03 HZ} \\

___________________________

\sf\underbrace{Hence,}

{: \longrightarrow}\sf\underline\red{Time~period~=0.33~seconds}

{: \longrightarrow}\sf\underline\pink{Frequency~=~3.03HZ}

___________________________

{ \longrightarrow}All done :p

           \bf\orange{@hotcupid16} \\

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