a body weigh 45 kg on the surface of the earth what will be its weight on the surface of Mars whose mass is 1 by 9 and the radius is one by two third of the earth
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The body weight is 90kg
so,the mass is 90kg
Mass of mars =1/9
Radius =1/2 of earth
F=mg=m(G M/Re 2)
F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth
F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2
=4/9
=90*4/9
=>mass of mars =40kg
so,the mass is 90kg
Mass of mars =1/9
Radius =1/2 of earth
F=mg=m(G M/Re 2)
F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth
F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2
=4/9
=90*4/9
=>mass of mars =40kg
user9432:
Ans. 20kg-wt
please mark me as brainlist
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