Physics, asked by aneekanara, 9 months ago

A body weighing 5 kgf. placed on a surface
of area 0.1 m? exerts a thrust on the surface
equal to:​

Answers

Answered by rekhamishramani
5

Explanation:

1 kgf =9.8Narea=0.1m^thurst=normal presure=force=9.8N

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