Question

A body weighing 5 Kgf, placed on a surface
of area 0.1 m², exerts a thrust on the
surface equal to
1. 50 Kgf
2 5kgf
3. 50kg m-2
7. 5 Kgf m-2​

Answer 1

Answer:

a thrust on the surface equal to the

Explanation:

1. 50 kgf

Answer 2

Answer:

The correct answer is Option B: $5kgf$

Explanation:

Given that:

Weight of the body$=5kgf$

Surface area$=0.1m^2$

Pressure $=\frac{Thrust}{Area}$

Thrust $=$ weight of the body

Thrust $= 5kgf$

Thrust:

The normal force acting on a surface is called thrust. Newton is its SI unit (N). The force that propels an airplane through the air is called thrust. In order to overcome the drag of an aircraft and the weight of a rocket, thrust is used.

Pressure:

Pressure is defined as the force perpendicular to an object's surface applied per unit area over which that force is dispersed.