a body weighing 50 kg is suspended with one side of spring and string which is connected to a 30kg body which is again connected to the surface by spring and string but on the alternate side. NL=30 cm K=20/cm. find tension of both string.
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M = 2.50 kg
T = 200 N
l = 20.0 m
Mass per unit length ,
μ =M/l = 2.50/20
=0.125Kgm−1
The velocity (v) of the transverse wave in the string is given by the relation:
∴ Time taken by the disturbance to reach the other end, = 0.5 sec
Explanation:
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