Question

a body weighing 80 Nis moved up a slope of angle 60 with the horizontal through a displacement of 1 m .............​

Answer 1

Answer:

Ans is 40√3

Explanation:

here mg=80N

Now here energy gets stored in the body as potential energy,,now we know potential energy=mgh

Here h= lsin60° ,(l=1m)

therefore h= √3/2

therefore potential energy=mgh=80×√3/2

= 40√3

HOPE IT HELPS

Answer 2

The energy of the body will be 69 J

Explanation:

Given weight of the body, W = 80 N

Slope of angle 60 with the horizontal.

The displacement of the body, d = 1 m

So the body will reach up to height,

$h=d\times sin(60^{0})$

 $h=1\times(\frac{\sqrt{3} }{2})=0.87m$

The energy of the body up to height h will be potential energy and given  as

$P=mgh=W\times h$

Substitute the given values, we get

$=80N\times 0.87m=69J$

Thus, the energy of the body will be 69 J

Topic : Potential energy

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