Question

A body weighs 1 kg on the surface of the moon. If mass of the moon is 7.4 ×10^22kg and radius of moon is 1740 km. Calculate the force acting between the body and the moon

Answer 1

⊕ANSWER⊕

We have,

Mass of the body is, m = 1 kg

Mass of moon is, M = 7.4 × 1022 kg

Radius of moon, R = 1740 km = 1740000 m

G = 6.67 × 10-11 Nm2/kg2

Now,

Force acting on the body is,

F = GMm/R2 = 1.63 N  

Same is the force acting on the moon.

Acceleration produced on the body is found as,

F = ma

=> a = F/m = 1.63/1 = 1.63 m/s2

Acceleration produced on the moon,

F = Ma/

=> a/ = F/M = 1.63/(7.4 × 1022)  = 2.2 × 10-23 m/s2.

Answer 2

Answer:

we have

mass of the body is,M=1kg

mass of the moon, M=7.4*1022kg

radius of Moon, R=1740km

=1740000m

G=6.67*10.11nm2/kg2

Now

force acting on the body is

F=Gmm/R2=1.63n

same is the force acting on the moon

acceleration produced on the body is found as

F=ma

a=f/m=1.63/1=1.63m/s2

acceleration produced on the moon

F=ma

a/=F/m=1.63/(7.4*1022)

=2.2*10-23m/s2