Question

a body weighs 200gf in air and 190gf completely immersed in water.caiculate the loss in weight of the body and the upthrust acting on the body.

Answer 1

Answer:

1. 10g

2. 10g

hope this helps

please mark as the brainliest

Answer 2

Answer:

The upthrust on the body exists at 10 gf.

Explanation:

A body weighs 200gf in air and 190 gf when completely dipped in water.

We have to estimate the loss in weight of the body in water and upthrust on the body.

By using Archimedes’ principle :

“When a particle exists entirely or partially dipped in a liquid, it participates a buoyant force comprehended as upthrust, exists equivalent to the weight of the liquid displaced by the particle.”

Loss in the weight of body = weight of the body in the air - the weight of the body in water

Weight of body in the air $= 200 gf$

weight of the body in water = 190 gf (when it exists completely submerged)

now, loss in the weight of the body $= 200gf - 190 gf = 10 gf$

Therefore the loss in the weight of the body exists at 10gf.

Buoyant force or upthrust = weight of the liquid displaced by body = loss in the weight of the body in water $= 10gf$

Therefore the upthrust on the body exists at 10 gf.

#SPJ3