Question

A body weighs 25 kg on the surface of the earth is 6×1024 kg the radius of the earth 6.4×106and thegravitayional consant =6.67×10-11 calculate.

1.the acceleration produced in the body

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Answer 1

Answer:

40.71 × 10-²⁴ m/s²

Explanation:

We know that ,    

So , using the above formula and substituting the values in it, we      

Hence, the acceleration produced on the body is 9.8 m/s².  

To find the acceleration produced on the Earth :  

We know that ,    

So , using the above formula and substituting the values in it, we get :    

Hence, the acceleration produced on the Earth is 40.71 × 10-²⁴ m/s²

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Answer 2

Answer:

Explanation:

Given, Me = 6 × 1024 kg,  m = 25 kg

Re = 6.4 × 106 m and

G = 6.67 × 10-11 N-m2/kg2

(i) Mutual force,

 F = G Me R2e

m

 = 6.67 × 10−11 6 × 1024 × 25 (6.4 × 106)2

= 244 N

(ii) Acceleration produced in the body,

 a = F m

= 244 25

= 9.8 m/s2

(iii) Acceleration produced in the earth,

 a = F Me

= 244 6 × 1024  = 4.06 × 10-23 m/s2