Physics, asked by kavithaparani76, 3 months ago

A body weighs 340 gf in air and 312 gf when completely immersed in water. Calculate:

(i) the loss in weight of the body in water, (ii) the upthrust on the body.​

Answers

Answered by archanashingne87
1

Answer:

Weight of the body in air, W = 450 gf = 450g dynes

Weight of the body in water, W/ = 310 gf = 310g dynes

Let, d be the density of the body, V be its volume. Let q be the density of water.

Now,

W = Vdg

=> 450g = Vdg

Buoyant force, B = Vqg

=> B = Vg [q = 1 g/cm3]

Now, W/ = W – B

=> 310g = 450g – Vg

=> V = 140 cm3

Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf

Again, upthrust = Buoyant force = 140 gf

Explanation:

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