A body weighs 36 kg on the surface of earth. How much would it weigh on the surface of a planet, whose mass is 1/9 and radius is 1/3 of that of earth?
Answers
Answered by
23
Hi Mate !!!
Mg = G M²/ r²....... equation 1
Mg is weight on earth.
G is universal gravitational constant
r is radius of earth.
(Mg)' = GM² / r'²
r' = r / 3 ,. M' = M /9
(Mg)' = G M²/ 9r²...... equation 2
(Mg)' weight on other planet
M' Mass of other plant.
r' is radius of other planet.
Dividing equation 1 and 2 we get
36 / (Mg)' = 9
(Mg)' = 4 N
!!!!!! Have a great future ahead dear!!!!!!!!
Mg = G M²/ r²....... equation 1
Mg is weight on earth.
G is universal gravitational constant
r is radius of earth.
(Mg)' = GM² / r'²
r' = r / 3 ,. M' = M /9
(Mg)' = G M²/ 9r²...... equation 2
(Mg)' weight on other planet
M' Mass of other plant.
r' is radius of other planet.
Dividing equation 1 and 2 we get
36 / (Mg)' = 9
(Mg)' = 4 N
!!!!!! Have a great future ahead dear!!!!!!!!
Answered by
7
"Mass m = 36 kg on Earth
weight = m g = m G M / R²
G = universal gravitational constant
M = mass of Earth
R = Radius of Earth
Mass of the body remains same on the surface of other planets.
gravity on a planet = g' = G M' / R' ²
M' = M/9 and R' = R/2
=> g ' = G M/R * 4/9 = 4 g / 9
weight on the planet = m g' = 4/9 m g = 4/9 * 36 kg = 40/3 kg
"
nia118261515:
hlo
Similar questions