Political Science, asked by TbiaSamishta, 11 months ago

A body weighs 36 kg on the surface of earth. How much would it weigh on the surface of a planet, whose mass is 1/9 and radius is 1/3 of that of earth?

Answers

Answered by Anonymous
23
Hi Mate !!!

Mg = G M²/ r²....... equation 1


Mg is weight on earth.

G is universal gravitational constant

r is radius of earth.

(Mg)' = GM² / r'²

r' = r / 3 ,. M' = M /9

(Mg)' = G M²/ 9r²...... equation 2


(Mg)' weight on other planet

M' Mass of other plant.

r' is radius of other planet.



Dividing equation 1 and 2 we get

36 / (Mg)' = 9

(Mg)' = 4 N



!!!!!! Have a great future ahead dear!!!!!!!!

Answered by aqibkincsem
7

"Mass m = 36 kg  on Earth

weight = m g = m G M / R²

         G = universal gravitational constant

         M = mass of Earth

         R = Radius of Earth


Mass of the body remains same on the surface of other planets.

gravity on a planet = g' = G M' / R' ²

                        M' = M/9        and  R' = R/2

    =>  g ' = G M/R * 4/9 = 4 g / 9

 

weight on the planet = m g' = 4/9 m g  = 4/9 * 36 kg = 40/3  kg

"


nia118261515: hlo
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