a body weighs 450 GF in a air and 310 gf when completely immersed in water find (i)the volume of a body(ii) the loss in weight of the body and(iii) the upthrust of the body.
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Weight of the body in air, W = 450 gf = 450g dynes
Weight of the body in water, W/ = 310 gf = 310g dynes
Let, d be the density of the body, V be its volume. Let q be the density of water.
Now,
W = Vdg
=> 450g = Vdg
Buoyant force, B = Vqg
=> B = Vg [q = 1 g/cm3]
Now, W/ = W – B
=> 310g = 450g – Vg
=> V = 140 cm3
Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf
Again, upthrust = Buoyant force = 140 gf
Weight of the body in water, W/ = 310 gf = 310g dynes
Let, d be the density of the body, V be its volume. Let q be the density of water.
Now,
W = Vdg
=> 450g = Vdg
Buoyant force, B = Vqg
=> B = Vg [q = 1 g/cm3]
Now, W/ = W – B
=> 310g = 450g – Vg
=> V = 140 cm3
Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf
Again, upthrust = Buoyant force = 140 gf
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