A body weighs 450 gf in air and 310 gf when completely immersed in water.
Calculate the loss in weight of the body in water.
Answers
Weight of the body in air, W = 450 gf = 450g dynes
Weight of the body in water, W/ = 310 gf = 310g dynes
Let, d be the density of the body, V be its volume. Let q be the density of water.
Now,
W = Vdg
=> 450g = Vdg
Buoyant force, B = Vqg
=> B = Vg [q = 1 g/cm3]
Now, W/ = W – B
=> 310g = 450g – Vg
=> V = 140 cm3
Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf
Again, upthrust = Buoyant force = 140 gf
Answer:
140gf
Step-by-step explanation:
Weight of the body in air, W = 450 gf = 450g dynes
Weight of the body in water, W/ = 310 gf = 310g dynes
Let, d be the density of the body, V be its volume. Let q be the density of water.
Now,
W = Vdg
=> 450g = Vdg
Buoyant force, B = Vqg
=> B = Vg [q = 1 g/cm3]
Now, W/ = W – B
=> 310g = 450g – Vg
=> V = 140 cm3
Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf
Again, upthrust = Buoyant force = 140 gf
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