Question

A body weighs 4n in air 3n in water and 2n in a liquid

Answer 1

relative density of liquid is 2

A body weighs 4N in air 3N in water and 2N in a liquid then calculate relative density....

weight of body in liquid = weight body in air - Buoyancy force

⇒2N = 4N - ρ_(liquid)gV

⇒ρ_(liquid)gV = 4N - 2N = 2N .......(1)

weight of body in water = weight of body in air - Buoyancy force

⇒3N = 4N - ρ_(water)gV

⇒ρ_(water)gV = 4N - 3N = 1N ........(2)

from equations (1) and (2) we get,

⇒ρ_(liquid)/ρ_(water) = 2/1 = 2

⇒ relative density of liquid = 2

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Answer 2

$\huge\bold\purple{Answer:-}$

weight of body in liquid = weight body in air - Buoyancy force

⇒2N = 4N - ρ_(liquid)gV

⇒ρ_(liquid)gV = 4N - 2N = 2N .......(1)

weight of body in water = weight of body in air - Buoyancy force

⇒3N = 4N - ρ_(water)gV

⇒ρ_(water)gV = 4N - 3N = 1N ........(2)

from equations (1) and (2) we get,

⇒ρ_(liquid)/ρ_(water) = 2/1 = 2

⇒ relative density of liquid = 2