Question

A body weighs 60 g in air. If its volume is 10cc in water, How much will it weigh in water?

Answer 1

Relative Density = (Weight of solid in air) / (Weigh of water displaced by the solid)   ---------------------(1)

RD = (Wt of solid in air) / (Apparent loss of wt of the body in water)----------(2)

Where Apparent loss of wt of the body in water = ΔW = Wt of solid in air - Wt of solid in water

Given:

Wt of solid in air = 60 g

Volume of solid in water = 10 cc

From Archimedes Principle we know that Vol. of solid immersed = Vol. of liquid displaced

∴ 10 cc of water has been displaced

We know ρ(Density) = Mass/Vol.

ρ(Water) = 1 g / cc

∴ 1 g / cc = Mass(of water displaced) / 10 cc

Mass(of water displaced) = 10 g

Using equation (1)

RD = 60/10 = 6

Now using equation (2)

6 = 60 / ΔW

ΔW = 10 g = Wt of solid in air - Wt of solid in water

10 g = 60 g  - W(Solid in water)

W(Solid in water) = 50 g

Answer 2

Answer:

the number of the brainliest is a potent than the to the number my time in my life with you y you are not the number be able to make a difference for your responsibility to cm CB radios to to run the brainliest the following URL is the best