Question

A body weighs 64N on the surface of the earth, what is the gravitational force on it due to earth at a height equal to the radius of the earth?

Answer 1

hope this would help u

Answer 2

Initial force exerted:
F = mg 
   = 63 N
Mass of body:
M = f/g
    = 63/10 kg = 6.3 kg
Variation in g by height:
g₁ = g/(1+(h/R))²
Then,
g₁ = g(1+R/2R))²
g₁ = g/(3/2)² or g₁ = (4/9)g = 4.44m/s²
Now,
F₁ = 6.3 × 4.4 = 27.72 N     ANS