A body weighs 72 N on the surface of the earth.
What is the gravitational force on it at a height
equal to half the radius of the earth from the
surface ?
1) 72 N
2) 28 N.
3) 16 N
4732 N
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ANSWER
Weight of body on the surface of the earth = mg= 72 N
Acceleration due to gravity at height h is
gh=(RE+h)2gRE2
=(RE+2RE)2gRE2
=94g(∵h=2RE)
Gravitational force on body at height h is
F=mgh
=m×94g=94×mg
=94×72N=32N
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