Question

a body weighs 72n on surface of the earth what is the gravitational force on it due to earth at a height 1/4 of radius from the earth surface​

Answer 1

Answer:

Explanation:

ANSWER

At the surface of Earth, weight W=72N

∴F=mg=72N

m=  

10

72

​  

=7.2kg

Now, at some height, h acceleration due to gravity is given as  

g  

′

=  

(1+  

R

h

​  

)  

2

 

g

​  

 

Here, h=  

2

R

​  

 

g  

′

=  

(1+  

2

1

​  

)  

2

 

g

​  

=  

9

4

​  

g=4.44m/s  

2

 

Now, the force experienced by the body at half of the radius of the earth is given by:  

F  

′

=mg  

′

=7.2×4.44=31.97N≈32N