A body weighs 72N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth?
(a) 16 N.
(b) 28 N
(c) 32 N
(d) 72 N
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Weight of body on the surface of the earth =mg=72N
Acceleration due to gravity at height h is
gh=(RE+h)2gRE2
Substitute h=2RE in above expression:
gh=(RE+2RE)2gRE2
=94g
Gravitational force on body at height h is
F=mgh
=m×94g=94×mg
=94×72N=32N
Therefore , the correct option is c.
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Answer:
Complete answer:
On the surface of the Earth, i.e., at a height R (where R is the radius of the Earth), F=mg=72N. Hence, the correct choice would be 32 N.
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