Question

a body weighs 75 gf in air, 70.5gf in water and 66 gf in a liquid, calculate the density of the liquid. (gf= gram force)

Answer 1

relative density of liquid

= density of liquid / density of water
= buoyancy force in liquid / buoyancy force in water
= Loss of weight in liquid / loss of weight in water
= [ weight of object in air - weight of object in liquid ] / [ weight of object in air - weight of object in water ]

= [ 75 - 70.5 ] / [ 75 - 66 ]
= 4.5 / 9
= 0.5

Density of liquid = 0.5 * density of water
= 0.5 * 1000 kg / m^3
= 500 kg/m^3

Answer 2

Answer:

Density of Liquid= 2000kg/m^3

Explanation:

Relative Density=

$(w1 - w3) \div (w1 - w2)$

=> (75-66)/(75-70.5)

=> 9/4.5

=> 2

Hence,Relative Density=2

To find Density of Liquid,

=>Relative Density×Density of Water

=>2×1000kg/m^3

=>2000kg/m^3

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