Physics, asked by jahnvisharma1712, 1 month ago

A body weighs 78 g-wt in air. It displaces 13 g-wt water when completely immersed in it
(1) what is the apparent weight of the body?
(11) what is the buoyancy on the body?
(III) what is the volume of displaced water?
(IV) what is the volume of the body?​

Answers

Answered by barani7953
2

Explanation:

Given the volume of the body is V=10 cc

Weight of the body in air is W=40 g wt

By Archimedes principle, the buoyant force on the body when immersed in water is B=ρgV=1g/cc×g×10 cc=10 g wt

Thus, weight in water is W

=W−B=40−10=30 g wt

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