a body weighs 80n on surface of earth at what height from earth will it weigh 5N
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Answer:-
The body will weigh 5N at a height of 19200 km from the surface of Earth.
Explanation:-
•Radius of Earth = 6400km
Let the required height be h km.
Weight at a height of h km:-
=> Wₕ = mgₕ
=> Wₕ = mg(R/R+h)²
[ ∵ gₕ = g(R+R/h)² ]
Here, mg = 80N, R = 6400km, Wh = 5N
=> 5 = 80[6400/6400+h]²
=> 5/80 = [6400/6400+h]²
=> 1/16 = [6400/6400+h]²
=> √1/16 = √[6400/6400+h]²
=> 1/4 = 6400/6400+h
=> 6400+h = 6400×4
=> 6400+h = 25600
=> h = 25600-6400
=> h = 19200 km
Thus, required height is 19200 km from the surface of Earth.
Some Extra Information:-
•Weight of a body on the Earth is the force with which the Earth attracts a body.
•Weight is a vector quantity
•The S.I. unit of weight is Newton.
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