Question

a body weighs 80N on the surface of earth.What is its weight on the on the surface of Earth.(given acceleration due to gravity on Earth is 6times that of the moon

Answer 1

I'm not really sure but I think
80 ×6 =480kg
Because 1/6×kg=N

Answer 2

Ques. A body weighs 80 N on the surface of the earth. What is its weight at a height equal to radius of the earth?

A 40 N

B 60 N

C 30 N

D 20 N

Answer:

The correct answer is option D $20 N$.

Thus, The weight of body at a height equal to radius of the earth is $20 N$.

Explanation:

Concept:

The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. An object's velocity changes when it falls freely toward the surface of the earth from a specific height. This acceleration is known as acceleration due to gravity and is symbolised by the symbol $g$.

Given:

The weighs of body at earth$= 80N$

To find:

We have to find its weight at a height equal to radius of the earth.

Solution:

Acceleration due to gravity at height $h$ above the surface of earth is given by

$g'=\frac{gR^{2}}{(R+h)^{2} }$

$mg'=\frac{mgR^{2}}{(R+h)^{2} }$

$mg'=\frac{mgR^{2}}{(2R)^{2} }$

$mg'=\frac{mg}{4} }$

$=\frac{80}{4} \\=20N$

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