Question

A body weighs 90 kg on the surface of earth how much will it weigh on surface of mars whose mass is 1/9 and radius 1/2 of that of earth?

Answer 1

Weight ∝ M / R²

W1 / W2 = (M1 / M2) × (R2 / R1)^2
W2 = W1 × (R1 / R2)^2 × (M2 / M1)
W2 = 900 × (R1 / (R1/2))^2 × ((M1/9) / M1)
W2 = 900 × 4 × 1/9
W2 = 400 N

Weight of object at Mars will be 400 N

Answer 2

Answer:

Answer:

The body weight is 90Kg

so,the mass is 90N

Mass of mars =1/9

Radius =1/2 of earth

F=mg=m(G M/Re 2)

F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth

F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2

=4/9

=90*4/9

=>mass of mars =40Kg