A body weighs 90 kg on the surface of Earth. How much Will it weigh on the surface of Mars , whose mass is 1/9 th and radius 1/2 that of earth=?
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Answered by
8
weight of the body on surface of Earth = 90N
(there must be a mistake in question as weight is measured in Newton not in Kg).
GM/R^2 = 10m/s^2 on earth ------(i)
Then mass of the body = 90/10= 9 kg
Mass of Mars = (1/9)(M) = M/9
Radius of Mars = (1/2)R = R/2
Now, acceleration causes by the planet =
{G(M/9)} \ (R/2)^2
= 4GM / 9R^2
= (4/9)(GM/R^2)
From (i)
we got
(4/9)(10)
= 40/9
And this the acceleration due to gravity on Mars.
As mass doesn't changes,
Hence, weight of that body on thia new planet = (40/9)(9)
= 40N.
(there must be a mistake in question as weight is measured in Newton not in Kg).
GM/R^2 = 10m/s^2 on earth ------(i)
Then mass of the body = 90/10= 9 kg
Mass of Mars = (1/9)(M) = M/9
Radius of Mars = (1/2)R = R/2
Now, acceleration causes by the planet =
{G(M/9)} \ (R/2)^2
= 4GM / 9R^2
= (4/9)(GM/R^2)
From (i)
we got
(4/9)(10)
= 40/9
And this the acceleration due to gravity on Mars.
As mass doesn't changes,
Hence, weight of that body on thia new planet = (40/9)(9)
= 40N.
Answered by
2
Answer:
Answer:
The body weight is 90N
so,the mass is 90N
Mass of mars =1/9
Radius =1/2 of earth
F=mg=m(G M/Re 2)
F mars /F earth = m (G M / R e 2)mars/m (G M/R e 2)earth
F mars/90 kg =(M earth/9)/m earth *(r earth)e 2/{r earth /2}e 2
=4/9
=90*4/9
=>mass of mars =400N
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