A body weighs W Newton of the surface of the earth. its weight at a height equal to half of the radius of the earth will be a
Answers
Answered by
35
Ahoy
______________________________________________________________________________________________________________________________
R= 6400km
W= mg
g= W/m
_____________________________________________________________
now the weight of the body at the height = 1/2 of R
______________________________________________________________
g'= g ( 1- d/R )
Weight of the body at the 1/2 R
W' = W(1- R/2R )
W' = W ( R / 2R )
W' = 1/2 W Newton
___________________________________________________________________________________________________________________________
Hope it helps you : ]
______________________________________________________________________________________________________________________________
R= 6400km
W= mg
g= W/m
_____________________________________________________________
now the weight of the body at the height = 1/2 of R
______________________________________________________________
g'= g ( 1- d/R )
Weight of the body at the 1/2 R
W' = W(1- R/2R )
W' = W ( R / 2R )
W' = 1/2 W Newton
___________________________________________________________________________________________________________________________
Hope it helps you : ]
Answered by
93
hope it is correct answer would be 4W/9
Attachments:
Similar questions