Question

a body weight 1,000 n can produce a pressure 10°6 Pascal. calculate the area of cross section where force will act

Answer 1

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Given :- }}}}$

• A body of weight 1000N can produce a pressure of 10⁶ Pascal .

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ To Find :- }}}}$

• The Area over which it acts.

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Solution :- }}}}$

We know that Pressure is defined as Force/Area . Here force is provided in the form of weight of the body . On substituting the respective values , we have ,

$\sf\dashrightarrow Pressure ( P) =\dfrac{Force(F)}{Area(A)} \\\\\\\sf\dashrightarrow 10^6 N = \dfrac{ 1000 N }{Area} \\\\\\\sf\dashrightarrow Area = \dfrac{ 10^3}{10^6} m^2 \\\\\\\sf\dashrightarrow Area = 10^{-3} m^2 \\\\\\\sf\dashrightarrow \underset{\blue{\sf Required\ Area }}{\underbrace{\boxed{\pink{\frak{ Area = 0.001 \ m^2 }}}}}$