Question

a body weight 1,000 n can produce a pressure 10°6 Pascal. calculate the area of cross section where force will act​

Answer 1

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Given :- }}}}$

• A body of weight 1000 N can produce a pressure of 10⁶ Pascal

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ To \: Find :- }}}}$

• The Area over which it acts.

$\red{\bigstar}\underline{\underline{\textsf{\textbf{ Solution:- }}}}$

We know that Pressure is defined as Force/Area . Here force is provided in the form of weight of the body . On substituting the respective values , we have ,

$\begin{gathered}\sf\dashrightarrow Pressure ( P) =\dfrac{Force(F)}{Area(A)} \\\\\\\sf\dashrightarrow 10^6 N = \dfrac{ 1000 N }{Area} \\\\\\\sf\dashrightarrow Area = \dfrac{ 10^3}{10^6} m^2 \\\\\\\sf\dashrightarrow Area = 10^{-3} m^2 \\\\\\\sf\dashrightarrow \underset{\blue{\sf Required\ Area }}{\underbrace{\boxed{\pink{\frak{ Area = 0.001 \ m^2 }}}}}\end{gathered}$

Answer 2

Answer:

★ Given :

A body of weight 1000 N can produce a pressure of 10⁶ Pascal

★ To Find :

The Area over which it acts.

★ Solution :

We know that Pressure is defined as Force/Area . Here force is provided in the form of weight of the body .

On substituting the respective values ,

We have :

• Weight = Force = 1000 N
• Pressure = 10⁶ Pa
• Area = ?

Pressure(P) = Force(F) / Area(A)

• 10⁶ = 10³ / A

• 10⁶ / 10³ = 1 / A

• 10³ = 1 / A

• A = 1 / 1000

• A = 0.001 m²

⭐ The area of cross section where force will act is 0.001 m² .

➡ 0.001 m²