A body weight 100N on the surface of Earth how much will it weight at a heigh equal to half the radius of earth?
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Answered by
13
Heya Mate Your Answer is..!!
For distance between object and centre of the earth we haveAcceleration due to gravity at height be gh = (R/R + h)^2
mg1 = GMm / (R + h)^2gh = GM/(R + h)^2
Now
gh/g = R^2/(R + h)^2
or gh = g(R/R + h)^2
given
h = R/2gh = g(R/R+R/2)^2 gh = g(2R / 3R)^2 = g x 4/9
Acceleration due to gravity at depth = R/2gD = g(1 - D/R)gD = g(1 - R/2/R) = g/2Wh / WD = gh /gD = 4g/9 / g/2= 4g/9 x 2/g = 8/9 = 0.8888
Hope iT HelP YOu DEaR
Answered by
0
Explanation:
it will weigh something like 0.8888
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