a body weight 25kg on the surface of the earth. if the mass of the earth is 6×10^29kg, the radius is 6.4×10^6m, G= 6.67×10^-11 Nm^2/kg^2. the calulate force of attraction between the body and earth.
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Dear Friend We can apply Newtons law of gravitation to the abive question.
F=Gm1m2/r^2
= 6.67×10^-11 × 25 × 6× 10^29/(6.4×10^6)^2
= 24.52 × 10^6 Newton.
F=Gm1m2/r^2
= 6.67×10^-11 × 25 × 6× 10^29/(6.4×10^6)^2
= 24.52 × 10^6 Newton.
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