A body weight 30 gm in air and 26 gm when it is completely immersed in liquid of relative density find the volume of the solid and the relative density of solid brainly
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According to Archimedes principle,
Upthrust = Weight of liquid displaced
Weight of water displaced = 80-64 = 16
Now, density of water = 1g/cm³
1 g/cm³ = 16 g / x cm³
Therefore, volume of water displaced =
x = 16 cm³
So, volume of the solid = 16 cm³
It density = Mass/volume = 80/16 = 5 g/cm³
Relative density = Density of solid /Density of water = 5/1 = 5
Now, since the solid's density is more than water, it will sink in water.
Upthrust = Weight of liquid displaced
Weight of water displaced = 80-64 = 16
Now, density of water = 1g/cm³
1 g/cm³ = 16 g / x cm³
Therefore, volume of water displaced =
x = 16 cm³
So, volume of the solid = 16 cm³
It density = Mass/volume = 80/16 = 5 g/cm³
Relative density = Density of solid /Density of water = 5/1 = 5
Now, since the solid's density is more than water, it will sink in water.
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Answer:
Explanation:
hey here is your answer...........
when a body covers equal distances in equal interval of time then it is said uniform motion
when a body cover unequal distances in equal interval of time then it is said to be non uniform motion.
hope it is helpful
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