Question

a body weight 450 g in air and 310 g when completely immersed in water what is the upthrust on the body

Answer 1

Weight of the body in water, W/ = 310 gf = 310g dynes

Let, d be the density of the body, V be its volume. Let q be the density of water.

Now,

W = Vdg

=> 450g = Vdg

Buoyant force, B = Vqg

=> B = Vg [q = 1 g/cm3]

Now, W/ = W – B

=> 310g = 450g – Vg

=> V = 140 cm3

Loss in weight = Buoyant force = Vqg = 140 × 1 × g = 140g dynes = 140 gf

Again, upthrust = Buoyant force = 140 gf

Answer 2

Answer:

Answer is right bye bye

Explanation:

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