Question

A body weight 50 grams in air and 40 grams in water. Find its relative density
Give me complete solution then I will mark it as the braniliest answer

Answer 1

Answer:

5 la yauww.....

Explanation:

First, let's define the variables involved

w' : apparent weight

w : original weight

Fb : buoyant force / upward force

Their correlation can be expressed as follow :

w' = w - Fb

hence, Fb = w - w'

dividing all sides by w, we will obtain

(Fb / w) = 1 - (w' / w)

Since Fb = ρf × g × V  (ρf is the density of the liquid)

and w = ρ × g × V  (ρ is the density of the object)

g is the gravity acceleration and V is the volume of the solid object

substituting them will produce

(ρf × g × V) / (ρ × g × V)  =  1 - (w' / w)

canceling g and V, we will get

(ρf / ρ) = 1 - (w' / w)

now, submitting their values,

(ρf / ρ) = 1 - (40 g / 50 g)

(ρf / ρ) = 1 - 0.8  

(ρf / ρ) = 0.2  ==> (ρ / ρf) = 1 / 0.2  =  5

So, the relative density of the object [compared to water] is 5.

Hope this helps.

Regards,

Guru of Shinjuku Learning Support

shinjukulearning-dot-blogspot-dot-com