Question

A body weight 63n on surface of earth what is gravitatio al force on it due to earth at jeight half radius of earth

Answer 1

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Weight of the body, W = 63 N

Weight of the body, W = 63 NAcceleration due to gravity at height h from the Earth’s surface is given by the relation:

g‘ = g / [1 + ( h / Re) ]2

Where,

,g = Acceleration due to gravity on the

Earth’s surface

Earth’s surfaceRe = Radius of the Earth

For h = Re / 2

h = Re / 2g‘ = g / [(1 + (Re / 2Re) ]2

h = Re / 2g‘ = g / [(1 + (Re / 2Re) ]2= g / [1 + (1/2) ]2 = (4/9)g

Weight of a body of mass m at height h is given as:

W‘ = mg

W‘ = mg= m × (4/9)g = (4/9)mg

W‘ = mg= m × (4/9)g = (4/9)mg= (4/9)W

W‘ = mg= m × (4/9)g = (4/9)mg= (4/9)W= (4/9) × 63 = 28 N.

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