Physics, asked by njhambh4066, 1 year ago

A body weight 90kgf on the surface of the earth. How much will it weight on the surface of the mars whose mass is 1/9 and the radius is 1/12 of that of the earth

Answers

Answered by saaketsuryap26cen
1
If a body weighs 90N on earth it's mass would be 90/9.8 which is equal to 9.18
Remember:mass is same anywhere in the universe

Keeping this in mind let's proceed with the solution
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Answered by Ladylaurel
2

Answer:

<b> Acceleration due to gravity is calculated as

a = GM / R²

Where M = Mass of Planet and R is radius of Planet.

For earth

9.8 = GM / R² …………(1)

For Mars

g = G × (M/9) / (R / 2)²

g = (4/9) × GM / R²

g = (4/9) × 9.8 ………[∵ from (1)]

g = 4.35 m/s²

Now,

Weight of body = mg

= 90 kg × 4.35 m/s²

= 392 N

Weight of 90 kg body on surface of Mars is 392 N

[Note: If weight of body on surface of earth is 90 N then on surface of Mars it’s weight is 90 × 4/9 = 40 N]

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