A body weights 100N in air and 80N when submerged in water. Calculate the upthrust seting on the body.
Answers
Answered by
10
Weight difference =
150-100 = 50 N = Buoyant force of water
Buoyant Force in water(Fb) = density of water x g x volume of body(Vb)
50 = 1000 x 9.81 x Vb
Vb = 50/9810 cubic meter
Now, in air
Weight of body = mg = 150 N
Mass of body,m = 150/9.81 Kg
So,
Density of body = m/ Vb
= 150/9.81 ÷ 50/9810
= 3000 kg per cubic meter
Specific gravity of body = density of body ÷ density of water
= 3000 ÷ 1000
Specific gravity of body = 3.
150-100 = 50 N = Buoyant force of water
Buoyant Force in water(Fb) = density of water x g x volume of body(Vb)
50 = 1000 x 9.81 x Vb
Vb = 50/9810 cubic meter
Now, in air
Weight of body = mg = 150 N
Mass of body,m = 150/9.81 Kg
So,
Density of body = m/ Vb
= 150/9.81 ÷ 50/9810
= 3000 kg per cubic meter
Specific gravity of body = density of body ÷ density of water
= 3000 ÷ 1000
Specific gravity of body = 3.
snorinelihaviparqr2:
thank you
Similar questions