A body weights 450 N on the surface of Earth.
How much will it weigh on the surface of a
planet whose mass is ⅑
mass of Earth and
radius is half of radius of Earth?
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2
Answer:
50 N
as we know that F=GMm/R^2=450N ------i)
now m1=1/9m
so, F1=GMm1/R^2
=GMm/9R^2
=1/9×GMm/R^2
= 1/9×450. (from I)
=50N
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