Question

a body weights 450N on the surface of the earth.How much will it weigh on the surface of a planet whose mass is 1/9th mass of earth and radius is half of radius of earth

please answer quickly ​

Answer 1

Answer:-

Let the mass of the earth be "M" and it's radius be R.

Given:

Weight of the object on the earth = 450 N

We know that,

Gravitational force (F) = GMm/r²

Where, m is the Mass of the object and G is the gravitational constant.

→ F between Object and earth = GMm/r²

→ GMm/r² = 450 N. -- equation (1)

And,

Mass of the planet = 1/9 * mass of earth

→ Mass of the planet = 1/9 * M = M/9

Radius of the planet = 1/2 * radius of earth

→ Radius of the planet = 1/2 * (r) = r/2

Hence,

→ F between Object and planet = (G * M/9 * m) / (r/2)²

→ F between Object and planet = [ (GMm) / 9 ] / (r² / 4)

→ F between Object and planet = (GMm) / 9 * (4 / r²)

→ F between Object and planet = (GMm) / r² * 4/9

Putting the values from equation (1) we get,

→ F between Object and planet = 450 * 4 / 9

→ F between Object and planet = 200 N

Hence, the Object weighs 200 N on the planet.