Question

a body weights 63N on surface of earth. what is the gravitational force on it due to earth at a height equal to half the radius of earth?

Answer 1

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Weight of the body, W = 63 N

Acceleration due to gravity at height h from the Earth’s surface is given by the relation:

g‘ = g / [1 + ( h / Re) ]2

Where,

g = Acceleration due to gravity on the Earth’s surface

Re = Radius of the Earth

For h = Re / 2

g‘ = g / [(1 + (Re / 2Re) ]2

= g / [1 + (1/2) ]2  =  (4/9)g

Weight of a body of mass m at height h is given as:

W‘ = mg

= m × (4/9)g  =  (4/9)mg

= (4/9)W

= (4/9) × 63  =  28 N.

Answer 2

your answer in the attachment!