Question

• A body, when acted upon by a force of 10 kgf, gel
displaced by 0.5 m. Calculate the work done by th
force, when the displacement is (i) in the directio
of force, (ii) at an angle of 60° with the force, an
(iii) normal to the force. (g = 10 N kg-1) med
Ans. (i) 50 J (ii) 25 J (iii) zer​

Answer 1

Given,

Force = 10 kgf

g = 10 m/s²

Force in Newton = (10*10) N

= 100 N

Displacement = 0.5 m

1. Work Done = Force*displacement

= 100*0.5 J

= 50 J

2. Work Done = Force*displacement*cos 60°

= 100*0.5*0.5 J

= 25 J

3. Work Done = Force*displacement*cos 90°

= 100*0.5*0

= 0 J

I hope this helps.