Question

A body when acted upon by a force of 10 kgf moves to a distance 0.5m in the direction of force . find the work done by the force . take 1kgf : 10 N

Answer 1

F = 10kgf = 100N

D = 0.5m

W = F.D

= 100 × 0.5

= 50J



Thanks

Answer 2

Alright I have solved it....

At first, Force= 10Kgf => 10×10N = 100N

Given, length of a displaced body is 0.5 m

g= 10 N kg^-1 (let's take this value of g)

Now, the displacement is in the direction of force so we know Cos 0°= 1

therefore, W= F×S (the work done is positive)

=> 100×0.5=50 J (ans)

Hope it helps....^•^