a body,when acted upon by a force of 10kgf,gets displaced by 0.5m calculate the work done by the force,when the displacement is (1) in the direction of force (2) at an angel of 60° with the force and (3) normal to the force.(g=10n kg–¹)
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1) force =mass x acceleration
=10 x 9.8
=98N
work=force x displacement=98 x 0.5=49 J
=10 x 9.8
=98N
work=force x displacement=98 x 0.5=49 J
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