A body when acted upon by a force of 10kgf moves a distance 0.5m in the direction of force.Find the work done by the force.Take 1kgf= 10N
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5
F = 10kgf = 100N
D = 0.5m
W = F.D
= 100 × 0.5
= 50J
D = 0.5m
W = F.D
= 100 × 0.5
= 50J
Answered by
2
Answer:
We know work done=force×displacement
Explanation:
work done is denoted by 'W'
Force is f
and displacement is s
So, W=f×s
here, f=10N
s=0.5m
Now, W=10×0.5
work done =5 J (joules)
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