Question

A body when projected vertically up, covers a total distance D during its time of flight. If there
were no gravity, the distance covered by it during the same time is equal to
(A) 0
(B)D
(C) 2D
(D) 4D​

Answer 1

Answer:

Let particle be projected with speed u, so total time of fligh.

$T \: = \frac{2 \:U}{g}$

D = 2×maximum hight.

$2 \times \frac{ {u}^{2} }{2g} = \frac{ {u}^{2} }{g}$

IF there is no gravity,then

$D' \: = u \times T \: = \frac{ {2u}^{2} }{g} \: = 2D \:$

so, correct answer is option (c) 2D

hope it help ✌️