Question

A body when released from the top of inclined plane of length 1m reaches the bottom after 4 sec. how much distance will it cover in first two seconds?

Answer 1

Explanation:

U=0m/s

t=4sec

a=9m/s2(acceleration due to gravity)

s=ut+21at2

s=0∗4+21∗9∗4∗4

s=72m

41of72=18m

Now,s=18m,u=0m/s,a=9m/s2

 s=ut+21at2

18=0∗t+21∗9∗t2=21∗9t2

t2=2∗2

hence,t=2