Question

A body which is accelerated uniformly covers a distance of 20m in 5th s and 32 m in 8th s after it had started its motion. Find the distance covered by it during the 3rd second of its motion.

Answer 1

Answer:

Assuming the body is under uniform acceleration, let the velocity at 5th and 8th second be v5 and v8.

v5=20m/s

v8=32m/s

Rate of change of velocity=(V8-V5) / Change in time.

This implies Uniform acceleration = (32–20)/2

Thus acceleration a=6 m/s2

Now, distance travelled in 3rd second is

Veloctiy at t=3 s. Let's call it V3

According the well known formula:

v = u + at

v3 = v5 + (6.2)

v3 = 20 + 12

v3 = 32 m/s

Thus the body will travel 32m in 3rd second.

Answer 2

Answer:

v = u + at

v3 = v5 + (6.2)

v3 = 20 + 12

v3 = 32 m/s

Step-by-step explanation:

answer=32m/s