Question

A body which is initially at rest covers a distance of 6 m in 4 seconds. Calculate the acceleration.
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Answer 1

Answer:

0.75m/s2

Explanation:

s = 6m

u = 0m/s

t = 4s

s = ut + 1/2*at2

or 6m = 0m/s * t + 1/2 * a(4s)2

or 6m = 1/2*(16s2)a

or a = 6m/16s2 * 2

       = 3/4 m/s2

       = 0.75m/s2

Answer 2

s = 6 m

u = 0 m/s

t = 4s

s = ut+1/2at^2

6m = 0 m/s × t + 1/2 a(4s)2

=6m× 16s2×2

=3/4 m/s^2

=0.75 m/s^2